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JEE Main levelSingle correct optionDifficulty 2 of 3o2254

Take the relative reactivities per hydrogen for $Cl X_{2}$ at 25 $^{\circ}$ C as primary : secondary : tertiary = 1 : 3.8 : 5. The alkane shown is monochlorinated at 25 $^{\circ}$ C. What percentage of the product mixture is the tertiary chloride (nearest whole number)?

A31%
B42%
C45%
D55%

Answer: C

The alkane is 2,3-dimethylbutane. Twelve primary H give

12 \times 1 = 12

; two tertiary H give

2 \times 5 = 10

. The tertiary chloride, 2-chloro-2,3-dimethylbutane, is

10/22 = 45.5%

, about 45%.

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