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JEE Main levelSingle correct optionDifficulty 2 of 3o2252

Take the relative reactivities per hydrogen for $Cl X_{2}$ at 25 $^{\circ}$ C as primary : secondary : tertiary = 1 : 3.8 : 5. The alkane shown is monochlorinated at 25 $^{\circ}$ C. What percentage of the product is the secondary chloride (to the nearest whole number)?

A33%
B44%
C56%
D76%

Answer: C

The alkane is propane. Primary:

6 \times 1 = 6

; secondary:

2 \times 3.8 = 7.6

. The 2-chloropropane share is

7.6/13.6 = 55.9%

, about 56%.

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