Answer: A, B, D
The alkene is 1-methylcyclopentene. Boron goes to the unsubstituted carbon and H to the carbon bearing the methyl, from the same face, so OH ends up on the CH carbon (not on the tertiary carbon) and is trans to the methyl. The achiral alkene is attacked equally from both faces, so the trans alcohol (1R,2R and 1S,2S) forms as a racemate. Statement C is therefore false.