Aniline does not undergo Friedel-Crafts alkylation or acylation because

A $- NH X_{2}$ is a meta director
Baniline is insoluble in all organic solvents
Cthe lone pair on nitrogen forms a complex with $AlCl X_{3}$ , converting $- NH X_{2}$ into a strongly deactivating group
Daniline is less reactive than benzene due to the -I effect of $- NH X_{2}$ alone

Answer: C

The basic nitrogen acts as a Lewis base towards

AlCl X_{3}

and gives a positively charged

- N X^{+} H X_{2} - AlCl X_{3} X^{-}

type substituent. This group is strongly electron-withdrawing and deactivates the ring, so Friedel-Crafts reactions fail. Aniline itself is a strongly activated ring and an o/p director.

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Aniline does not undergo Friedel-Crafts alkylation or acylation because

Answer: C

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