Propane is monochlorinated with $Cl X_{2}$ and light at room temperature. Assume the relative reactivity per hydrogen atom is primary : secondary $= 1 : 3.8$ . Calculate the percentage of 2-chloropropane in the monochloro product mixture (give the answer to one decimal place).

Numerical answer type, answer in %, tolerance 0.2.

Answer: 55.9 %

Propane has 6 primary H and 2 secondary H. Relative yields: primary

6 \times 1 = 6

, secondary

2 \times 3.8 = 7.6

. Percentage of 2-chloropropane

= \frac{7.6}{6 + 7.6} \times 100 = 55.9%