Answer: A, B
Only HBr shows the radical (peroxide) pathway; Br⋅ adds to the terminal carbon to give the more stable radical. So options 1 and 2 give 1-bromopropane and 1-bromo-2-methylpropane. HCl and HI add by the ionic Markovnikov route even with peroxide and give 2-chloropropane and 2-iodobutane.