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NEET levelSingle correct optionDifficulty 1 of 3o2011

The intermediate formed in the first (slow) step of the addition of HBr to propene in the dark is

Aa carbene
Ba carbanion
Ca carbocation
Da free radical

Answer: C

The

π

bond attacks H

^{+}

of HBr in the slow step, giving the isopropyl carbocation and

Br X^{-}

. The carbocation is then captured by bromide in a fast step.

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