Answer: A
N,N-Dimethylbenzamide is reduced to benzyldimethylamine. In the tetrahedral intermediate the amide anion is a very poor leaving group, so the O-Al bond breaks and an iminium ion forms and takes a second hydride. In an ester the alkoxide is a viable leaving group, so an aldehyde forms and is reduced to a primary alcohol. Both statements are true and R explains A.