Benzoic acid ( $C X_{6} H X_{5} COOH$ , 12.2 g) is converted to benzoyl chloride with excess $SOCl X_{2}$ (isolated yield 90%). The acid chloride is then treated with excess aniline and pyridine to give N-phenylbenzamide, $C X_{6} H X_{5} CONHC X_{6} H X_{5}$ (yield 80% for this step). Using H 1, C 12, N 14, O 16, calculate the mass of N-phenylbenzamide obtained in grams, to two decimal places.

Numerical answer type, tolerance 0.02.

Answer: 14.18

Molar mass of benzoic acid

= 7 (12) + 6 (1) + 2 (16) = 122

g/mol, so 12.2 g

= 0.100

mol. Molar mass of

C X_{13} H X_{11} NO

= 197

g/mol. Moles of amide

= 0.100 \times 0.90 \times 0.80 = 0.072

mol. Mass

= 0.072 \times 197 = 14.184

g, i.e. 14.18 g.