Aniline is shaken with benzoyl chloride, $\mathrm{C}{}_6\mathrm{H}{}_5\mathrm{COCl}$, and aqueous $\mathrm{NaOH}$ (Schotten-Baumann conditions). The product is:

The nucleophilic nitrogen of aniline attacks the acyl chloride and the $\mathrm{NaOH}$ neutralises the HCl formed. The product is $\mathrm{C}{}_6\mathrm{H}{}_5\mathrm{CONHC}{}_6\mathrm{H}{}_5$, N-phenylbenzamide. Phenyl benzoate would need phenol, and benzophenone needs Friedel-Crafts acylation.