Compound X has 40.0% C, 6.67% H and 53.3% O by mass and molar mass 60 g mol^-1. Glucose is C6H12O6 (C = 12, H = 1, O = 1

Question

Compound X has 40.0% C, 6.67% H and 53.3% O by mass and molar mass 60 g mol^-1. Glucose is C6H12O6 (C = 12, H = 1, O = 16). Select the correct statement(s).

Accepted Answer

X and glucose have the same percentage composition.

Accepted Answer

The molecular formula of X is C2H4O2.

Accepted Answer

The empirical formula of X is CH2O.

Answer

6 g of X contain 0.2 mol of H atoms.

Compound X has $40.0%$ C, $6.67%$ H and $53.3%$ O by mass and molar mass $60 g mo l^{- 1}$ . Glucose is $C X_{6} H X_{12} O X_{6}$ (C = 12, H = 1, O = 16). Select the correct statement(s).

Answer: B, C, D

More questions on Empirical and molecular formula, percentage composition

Compound X has 40.0% C, 6.67% H and 53.3% O by mass and molar mass 60 g mol−1. Glucose is CX6​HX12​OX6​ (C = 12, H = 1, O = 16). Select the correct statement(s).

Answer: B, C, D

More questions on Empirical and molecular formula, percentage composition

Compound X has $40.0%$ C, $6.67%$ H and $53.3%$ O by mass and molar mass $60 g mo l^{- 1}$ . Glucose is $C X_{6} H X_{12} O X_{6}$ (C = 12, H = 1, O = 16). Select the correct statement(s).