The mass percentage of nitrogen in urea, $\mathrm{CO}(\mathrm{NH}{}_2){}_2$, is (H = 1, C = 12, N = 14, O = 16):

More questions on Empirical and molecular formula, percentage composition

• A compound contains 40.0% C, 6.67% H and 53.33% O by mass (C = 12, H = 1, O = 16). Its empirical formula is: NEET level
• A hydrocarbon has empirical formula CH and molar mass 78 g mol^-1 (C = 12, H = 1). Its molecular formula is: NEET level
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• Complete combustion of 0.74 g of an organic compound containing C, H and O gives 1.76 g of CO2 and 0.90 g of H2O (C = 12, H = 1, O = 16). Th... JEE Main level
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