MolSynapsequestion bank
MolSynapse / Question bank / Mole Concept / Empirical and molecular formula, percentage composition
JEE Advanced levelSingle correct optionDifficulty 3 of 3mc180

A mixture of and contains Fe by mass. The mass percentage of in the mixture is (Fe = 56, O = 16)

  1. A
  2. B
  3. C
  4. D

Answer: C

Fe fraction in FeO = 56/72 = 0.7778; in Fe2O3 = 112/160 = 0.7000. Let w be the mass fraction of FeO: 0.7778w + 0.7000(1 - w) = 0.750, so w = 0.6429. Fe2O3 fraction = 0.3571, i.e. 35.7%.
Practice Mole Concept More on Empirical and molecular formula, percentage composition

More questions on Empirical and molecular formula, percentage composition