Haemoglobin contains $0.34%$ iron by mass. Assuming one Fe atom per molecule, the minimum molar mass of haemoglobin in $g mo l^{- 1}$ , to the nearest integer, is (Fe = 56).

Numerical answer type, answer in g/mol, tolerance 1.

Answer: 16471 g/mol

In 100 g of protein there are 0.34 g Fe. If each molecule has one Fe, one mole of protein contains 56 g Fe. Molar mass = 56 x 100/0.34 = 16470.59 g/mol, i.e. 16471.

Practice Mole Concept More on Empirical and molecular formula, percentage composition

Previous questionNext question

More questions on Empirical and molecular formula, percentage composition

A hydrocarbon contains 92.3% carbon and 7.7% hydrogen by mass and its vapour density is 39. Its molecular formula is (C = 12, H = 1) JEE Main level
Using C = 12 and H = 1, select the correct statement(s) about the mass percentage of carbon. JEE Main level
A fertiliser sample contains 40% ammonium sulfate, (NH4)_2SO4, by mass; the remainder has no nitrogen. The mass percentage of nitrogen in th... JEE Main level
Combustion of 1.78 g of an organic compound (C, H, N, O only) gives 2.64 g CO2 and 1.26 g H2O. In a Kjeldahl analysis, all the nitrogen in 0... JEE Advanced level
20 mL of a gaseous hydrocarbon C_xH_y is mixed with 100 mL of O2 and exploded. After cooling to the initial temperature and pressure (water ... JEE Advanced level
An oxide of a metal M (atomic mass 27) contains 52.94% of M by mass (O = 16). Select the correct statement(s). JEE Advanced level

Haemoglobin contains 0.34% iron by mass. Assuming one Fe atom per molecule, the minimum molar mass of haemoglobin in g mol−1, to the nearest integer, is (Fe = 56).

Answer: 16471 g/mol

More questions on Empirical and molecular formula, percentage composition

Haemoglobin contains $0.34%$ iron by mass. Assuming one Fe atom per molecule, the minimum molar mass of haemoglobin in $g mo l^{- 1}$ , to the nearest integer, is (Fe = 56).