17 g of NH3 and 48 g of O2 react as far as possible according to 4NH3 + 5O2 -> 4NO + 6H2O (N=14, O=16, H=1). Choose the correct statement(s).

O2 is present in 20% excess over the amount needed.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3mc073

$17 g$ of $NH X_{3}$ and $48 g$ of $O X_{2}$ react as far as possible according to $4 NH X_{3} + 5 O X_{2} 4 NO + 6 H X_{2} O$ ( $N = 14$ , $O = 16$ , $H = 1$ ). Choose the correct statement(s).

NH X_{3}

= 1 mol,

O X_{2}

= 1.5 mol;

NH X_{3}

needs 1.25 mol

O X_{2}

, so

NH X_{3}

limits. Excess

O X_{2}

= (1.5-1.25)/1.25 = 20% (A true).

NO

= 1 mol = 30 g (B true).

O X_{2}

left = 0.25 mol = 8 g, not 5.6 g (C false).

H X_{2} O

= 1.5 mol = 27 g, not 36 g (D false).