13.0 g of zinc (65 g/mol) is added to 100 mL of 3.0 M HCl: Zn + 2HCl -> ZnCl2 + H2. Choose the correct statement(s). (Molar volume at STP 22.4 L/mol.)

3.36 L of H2 is evolved at STP.

3.25 g of Zn is left unreacted.

3.36 L of H2 is evolved at STP.

3.25 g of Zn is left unreacted.

JEE Advanced levelOne or more correct optionsDifficulty 3 of 3mc072

$13.0 g$ of zinc ( $65 g/mol$ ) is added to $100 mL$ of $3.0 M$ $HCl$ : $Zn + 2 HCl ZnCl X_{2} + H X_{2}$ . Choose the correct statement(s). (Molar volume at STP $22.4 L/mol$ .)

Zn

= 0.2 mol;

HCl

= 0.100 x 3.0 = 0.3 mol.

Zn

needs 0.4 mol

HCl

> 0.3, so

HCl

is limiting (A false).

H X_{2}

= 0.15 mol = 3.36 L (B true).

Zn

used = 0.15 mol, left = 0.05 mol = 3.25 g (C true).

ZnCl X_{2}

= 0.15 mol, not 0.2 (D false).