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JEE Main levelSingle correct optionDifficulty 2 of 3mc060

For $Fe X_{2} O X_{3} + 3 CO 2 Fe + 3 CO X_{2}$ , $100 g$ of $Fe X_{2} O X_{3}$ ( $160 g/mol$ ) is heated with $56 g$ of $CO$ ( $28 g/mol$ ). Taking $Fe = 56$ and complete reaction of the limiting reagent, the mass of iron obtained is

A $74.7 g$
B $70 g$
C $35 g$
D $56 g$

Answer: B

Fe X_{2} O X_{3}

= 0.625 mol;

CO

= 2 mol.

CO

required = 3 x 0.625 = 1.875 mol < 2 mol, so

Fe X_{2} O X_{3}

limits.

Fe

= 2 x 0.625 = 1.25 mol = 70 g.

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