Complete combustion of ethane follows 2C2H6 + 7O2 -> 4CO2 + 6H2O. The volume of CO2 at STP formed from 6.0 g of ethane is (C = 12, H = 1; 22.4 L mol^-1):

JEE Main levelSingle correct optionDifficulty 2 of 3mc040

Complete combustion of ethane follows $2 C X_{2} H X_{6} + 7 O X_{2} 4 CO X_{2} + 6 H X_{2} O$ . The volume of $CO X_{2}$ at STP formed from $6.0 g$ of ethane is (C = 12, H = 1; $22.4 L mo l^{- 1}$ ):

n (C X_{2} H X_{6}) = 6.0/30 = 0.20

mol. Each mole gives

2

mol

CO X_{2}

, so

0.40

mol.

V = 0.40 \times 22.4 = 8.96 L