On strong heating, CaCO3 -> CaO + CO2. The mass of CaO obtained from 10 g of pure CaCO3 is (Ca = 40, C = 12, O = 16):

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On strong heating, $CaCO X_{3} CaO + CO X_{2}$ . The mass of $CaO$ obtained from $10 g$ of pure $CaCO X_{3}$ is (Ca = 40, C = 12, O = 16):

n (CaCO X_{3}) = 10/100 = 0.10

mol, giving

0.10

mol

CaO

(

M = 56

). Mass

= 0.10 \times 56 = 5.6 g

. The value

4.4

g is the mass of

CO X_{2}