A gas mixture of total mass 24 g contains equal masses of CH4 and SO2 (C = 12, H = 1, S = 32, O = 16). Using 22.4 L mol^-1 at STP, find the volume of the mixture at STP in litres (one decimal place).

JEE Advanced levelNumerical answerDifficulty 3 of 3mc016

A gas mixture of total mass $24 g$ contains equal masses of $CH X_{4}$ and $SO X_{2}$ (C = 12, H = 1, S = 32, O = 16). Using $22.4 L mo l^{- 1}$ at STP, find the volume of the mixture at STP in litres (one decimal place).

Numerical answer type, answer in L, tolerance 0.05.

Each gas has

12 g

n (CH X_{4}) = 12/16 = 0.75

n (SO X_{2}) = 12/64 = 0.1875

, total

= 0.9375

mol.

V = 0.9375 \times 22.4 = 21.0 L

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