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NEET levelSingle correct optionDifficulty 1 of 3mt194

In an Ellingham diagram of $Δ G^{\circ}$ against $T$ (per mole of $O X_{2}$ ), a metal whose oxide line lies lower than that of a second metal

Acan reduce the oxide of the second metal at that temperature
Bcannot reduce any oxide
Cis always a poorer reducing agent
Dforms a less stable oxide than the second metal

Answer: A

A lower line means a more negative

Δ G^{\circ}

of oxide formation, i.e. a more stable oxide. The metal can therefore take oxygen from the oxide of the second metal, which lies above.

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