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JEE Main levelSingle correct optionDifficulty 2 of 3mt199

In the Ellingham diagram, the line for $C + O X_{2} CO X_{2}$ is almost horizontal because

A $CO X_{2}$ is a very stable gas that does not change with T
Bthe number of moles of gas is the same on both sides, so $Δ S^{\circ} \approx 0$
Ccarbon is a solid so no entropy change occurs
D $Δ H^{\circ}$ is zero

Answer: B

One mole of

O X_{2}

gas gives one mole of

CO X_{2}

gas, so

Δ S^{\circ}

is small and the slope

- Δ S^{\circ}

is nearly zero.

Δ H^{\circ}

is large and negative.

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