A 94.0 g sample of nickel(II) oxide ore (80.0% NiO by mass, impurities inert) is reduced completely by CO to nickel, NiO + CO -> Ni + CO2. The crude nickel is then converted completely to Ni(CO)4 by excess CO. Using Ni = 59, O = 16, C = 12, the mass of Ni(CO)4 obtained is

JEE Advanced levelSingle correct optionDifficulty 3 of 3mt189

A 94.0 g sample of nickel(II) oxide ore (80.0% NiO by mass, impurities inert) is reduced completely by CO to nickel, $NiO + CO Ni + CO X_{2}$ . The crude nickel is then converted completely to $Ni (CO) X_{4}$ by excess CO. Using Ni = 59, O = 16, C = 12, the mass of $Ni (CO) X_{4}$ obtained is

n(NiO) = 0.800 x 94.0 / 75 = 1.0027 mol, which gives 1.0027 mol Ni. Each Ni gives one

Ni (CO) X_{4}

(M = 171 g/mol). Mass = 1.0027 x 171 = 171.5 g.