JEE Main levelSingle correct optionDifficulty 2 of 3mt070
Match List I with List II.
List I (compound): (1) HgS (2) PbS (3) ZnCOX3 (4) FeX2OX3. List II (treatment): (P) calcined, then the oxide is reduced with coke near 1673 K (Q) heating in air liberates the metal directly (R) partly roasted, then the oxide formed reacts with the remaining sulphide giving the metal (S) charged with coke, limestone and a hot air blast.
A1-Q, 2-R, 3-P, 4-S
B1-P, 2-R, 3-Q, 4-S
C1-Q, 2-R, 3-S, 4-P
D1-R, 2-Q, 3-P, 4-S
Answer: A
HgS+OX2Hg+SOX2 gives mercury directly (Q). Galena is partly roasted and then PbS+2PbO3Pb+SOX2 (R). ZnCOX3 is calcined to ZnO then reduced by coke (P). Haematite goes to the blast furnace (S).