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JEE Main levelSingle correct optionDifficulty 2 of 3mt070

Match List I with List II. List I (compound): (1) (2) (3) (4) . List II (treatment): (P) calcined, then the oxide is reduced with coke near 1673 K (Q) heating in air liberates the metal directly (R) partly roasted, then the oxide formed reacts with the remaining sulphide giving the metal (S) charged with coke, limestone and a hot air blast.

  1. A1-Q, 2-R, 3-P, 4-S
  2. B1-P, 2-R, 3-Q, 4-S
  3. C1-Q, 2-R, 3-S, 4-P
  4. D1-R, 2-Q, 3-P, 4-S

Answer: A

gives mercury directly (Q). Galena is partly roasted and then (R). is calcined to then reduced by coke (P). Haematite goes to the blast furnace (S).
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