JEE Advanced levelSingle correct optionDifficulty 3 of 3mt050
A 5.52kg sample of bauxite contains 75.0%AlX2OX3⋅2HX2O by mass (molar mass 138) and the rest is inert. It is digested as AlX2OX3+2NaOH+3HX2O2Na[Al(OH)X4] (water of hydration counted among the water). 80.0% of the aluminium is then precipitated as Al(OH)X3, which is ignited by 2Al(OH)X3AlX2OX3+3HX2O. With Na=23, O=16, H=1, Al=27, the mass of NaOH consumed in the digestion and the mass of alumina obtained on ignition are
A1.20 kg and 1.96 kg
B2.40 kg and 2.45 kg
C4.80 kg and 2.45 kg
D2.40 kg and 3.06 kg
Answer: B
Moles of hydrated alumina =5520×0.75/138=30. Each needs 2 mol NaOH, so NaOH =60×40=2.40kg. Aluminium present =2×30=60 mol; 80% precipitated gives 48 mol Al(OH)X3. Ignition gives half as many moles of AlX2OX3: 24 mol ×102=2.45kg.