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JEE Main levelSingle correct optionDifficulty 2 of 3nm083

The IUPAC name of is:

  1. Apent-1-en-4-ol
  2. Bpent-4-en-2-ol
  3. Cpent-3-en-2-ol
  4. D4-hydroxypent-1-ene

Answer: B

Number so the OH gets the lowest locant: from the CH3 end the carbinol carbon is C-2, from the other end it would be C-4. With this numbering the double bond is C-4=C-5. The name is pent-4-en-2-ol.
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