JEE Main levelSingle correct optionDifficulty 2 of 3nm083
The IUPAC name of CHX2=CH−CHX2−CH(OH)−CHX3 is:
Apent-1-en-4-ol
Bpent-4-en-2-ol
Cpent-3-en-2-ol
D4-hydroxypent-1-ene
Answer: B
Number so the OH gets the lowest locant: from the CH3 end the carbinol carbon is C-2, from the other end it would be C-4. With this numbering the double bond is C-4=C-5. The name is pent-4-en-2-ol.