Answer: A, B, C
The OH takes the lowest locant first. CHX2=CHCHX2CHX2OH is but-3-en-1-ol (true). CHX3CH(OH)CH=CHCHX3 numbered from the left gives OH at 2 and C=C at 3, so pent-3-en-2-ol (true). CHX2=C(CHX3)CHX2OH is 2-methylprop-2-en-1-ol (true). CHX3CH=CHCHX2CHX2OH is pent-3-en-1-ol, not pent-2-en-5-ol (false).