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JEE Advanced levelSingle correct optionDifficulty 3 of 3ie148

100 mL of buffer P (0.20 M HA, 0.10 M NaA) is mixed with 300 mL of buffer Q (0.10 M HA, 0.30 M NaA). With $p K_{a} (HA) = 4.76$ and $lo g 2 = 0.301$ , the pH of the mixture is

A5.06
B4.76
C5.24
D4.46

Answer: A

Total HA = 20 + 30 = 50 mmol; total A

^{-}

= 10 + 90 = 100 mmol. pH =

4.76 + lo g (100/50) = 4.76 + 0.301 = 5.061

.

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