JEE Main levelNumerical answerDifficulty 2 of 3ie140
Sodium acetate (82 g/mol) is dissolved in 250 mL of 0.40 M acetic acid to make a buffer with pH = pKa+0.301 (log2=0.301). Find the mass of sodium acetate in grams, to one decimal place (neglect volume change).
Numerical answer type, answer in g, tolerance 0.1.
Answer: 16.4 g
Acid = 0.10 mol; salt/acid = 2 so salt = 0.20 mol; mass = 0.20×82=16.4 g.