MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Ionic Equilibrium I
/
Buffer solutions and Henderson equation
JEE Main level
Numerical answer
Difficulty 2 of 3
ie139
A solution has 0.25 M
NH
X
3
and 0.10 M
NH
X
4
Cl
. Using
p
K
b
=
4.75
and
p
K
w
=
14
, find the pH to two decimal places.
Numerical answer type, tolerance 0.01.
Answer: 9.6479
pOH =
4.75
+
lo
g
(
0.10/0.25
)
=
4.75
−
0.398
=
4.352
; pH =
14
−
4.352
=
9.65
.
Practice Ionic Equilibrium I
More on Buffer solutions and Henderson equation
Previous question
Next question
More questions on Buffer solutions and Henderson equation
To 100 mL of 0.10 M acetic acid, V mL of 0.10 M NaOH is added so that pH = pK_a - 0.301 (log 2 = 0.301). Find V in mL, to one decimal place.
JEE Main level
500 mL of a buffer contains 0.20 M HA and 0.20 M NaA. Calculate the decrease in pH (a positive number, two decimals) on adding 0.005 mol of ...
JEE Main level
A buffer has 0.09 M acetic acid and 0.20 M sodium acetate. Taking pK_a = 4.74, find its pH to two decimal places.
JEE Main level
Sodium acetate (82 g/mol) is dissolved in 250 mL of 0.40 M acetic acid to make a buffer with pH = pK_a + 0.301 (log 2 = 0.301). Find the mas...
JEE Main level
A buffer contains 0.30 M of a weak acid HA (K_a = 1.8 x 10^-5) and 0.15 M of NaA. Find [H+] in units of 10^-5 M, to one decimal place.
JEE Main level
100 mL of a weak electrolyte solution is mixed with 100 mL of a strong electrolyte solution. Which of the following combinations give a buff...
JEE Main level