MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Ionic Equilibrium I
/
Buffer solutions and Henderson equation
JEE Main level
Numerical answer
Difficulty 2 of 3
ie134
A buffer contains 0.15 M of a weak acid HA (
p
K
a
=
3.80
) and 0.05 M of its sodium salt. Find the pH to two decimal places.
Numerical answer type, tolerance 0.01.
Answer: 3.3229
pH =
3.80
+
lo
g
(
0.05/0.15
)
=
3.80
−
0.477
=
3.323
i.e. 3.32.
Practice Ionic Equilibrium I
More on Buffer solutions and Henderson equation
Previous question
Next question
More questions on Buffer solutions and Henderson equation
Four buffers all have [acid] = [salt] and the same acid. Which has the highest buffer capacity?
JEE Main level
100 mL of a buffer of 0.10 M HA and 0.10 M NaA is diluted to 1.0 L with water. Assuming ideal behaviour, the pH of the diluted solution rela...
JEE Main level
60 mL of 0.10 M NH3 is mixed with 20 mL of 0.10 M HCl. Given pK_b = 4.74, log 2 = 0.301, pK_w = 14, the pH is
JEE Main level
To 500 mL of 0.20 M acetic acid, solid NaOH (molar mass 40 g/mol) is added (no volume change) to obtain pH = pK_a + 0.477 (log 3 = 0.477). F...
JEE Main level
To 100 mL of 0.10 M acetic acid, V mL of 0.10 M NaOH is added so that pH = pK_a - 0.301 (log 2 = 0.301). Find V in mL, to one decimal place.
JEE Main level
500 mL of a buffer contains 0.20 M HA and 0.20 M NaA. Calculate the decrease in pH (a positive number, two decimals) on adding 0.005 mol of ...
JEE Main level