JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ie105
100mL of 0.3MHCl is mixed with 200mL of 0.1MNaOH at 298 K. Use log3=0.477. Select the correct statement(s).
AThe pH of the solution is 1.48.
BThe pH of the solution is 0.52.
CThe resulting solution is acidic.
D[OHX−]=3.0×10−13M.
Answer: A, C, D
HX+=30 mmol, OHX−=20 mmol; excess HX+=10 mmol in 300mL, [HX+]=1/30=0.0333M. pH=log30=1+0.477=1.48. [OHX−]=10−14/0.0333=3.0×10−13M. The value 0.52 is wrong.