JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ie103
A 0.1M solution of a weak monobasic acid (Ka=1.0×10−5) is diluted to 0.025M at 298 K (use α≪1, log2=0.301). Select the correct statement(s).
AThe degree of ionisation doubles.
BThe pH increases by about 0.30.
C[HX+] becomes half of its original value.
DKa becomes half of its original value.
Answer: A, B, C
[HX+]=Kac: 10−3→5×10−4M (half), so pH rises by log2=0.30. α=Ka/c goes from 0.01 to 0.02 (doubles). Ka depends only on temperature and stays constant.