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JEE Main levelNumerical answerDifficulty 2 of 3ie082

$150 mL$ of $0.2 M$ $HCl$ is mixed with $100 mL$ of $0.25 M$ $NaOH$ . Calculate the pH of the mixture (298 K) to two decimal places.

Numerical answer type, tolerance 0.01.

Answer: 1.7

H X^{+}

= 30

mmol,

OH X^{-}

= 25

mmol; excess

H X^{+}

= 5

mmol in

250 mL

, so

[H X^{+}] = 0.02 M

.

pH = 1.699 \approx 1.70

.

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