Find the percentage ionisation of 0.2 M acetic acid (K_a=1.8x10^-5) using alpha=sqrtK_a/c. Give the answer to two decimal places.

JEE Main levelNumerical answerDifficulty 2 of 3ie080

Find the percentage ionisation of $0.2 M$ acetic acid ( $K_{a} = 1.8 \times 1 0^{- 5}$ ) using $α = K_{a} / c$ . Give the answer to two decimal places.

Numerical answer type, answer in %, tolerance 0.01.

α = 1.8 \times 1 0^{- 5} /0.2 = 9 \times 1 0^{- 5} = 0.00949

, i.e.

0.95%