JEE Advanced levelNumerical answerDifficulty 3 of 3ie042
60mL of 0.15MHCl and 80mL of 0.05MHX2SOX4 are mixed with 25mL of 0.20MBa(OH)X2. Treating HX2SOX4 as fully ionised (ignore any precipitate effects on pH) and volumes as additive, find the pH to two decimals.
Numerical answer type, tolerance 0.01.
Answer: 1.37
n(HX+)=9+8=17mmol; n(OHX−)=2×5=10mmol. Excess HX+=7mmol in 165mL gives [HX+]=0.0424M and pH=1.372≈1.37.