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Ionic Equilibrium II
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Polyprotic acids and amphiprotic species
JEE Advanced level
Single correct option
Difficulty 3 of 3
ia204
Hydrogen sulfide is bubbled into
0.20
M
HCl
until
[
H
X
2
S
]
=
0.10
M
. Taking
[
H
X
+
]
=
0.20
M
and
K
a
1
K
a
2
=
1.0
×
1
0
−
21
, the concentration of
S
X
2
−
is
A
5.0
×
1
0
−
22
M
B
1.0
×
1
0
−
22
M
C
2.5
×
1
0
−
20
M
D
2.5
×
1
0
−
21
M
Answer: D
[
S
X
2
−
]
=
K
a
1
K
a
2
[
H
X
2
S
]
/
[
H
X
+
]
2
=
1
0
−
21
×
0.10/
(
0.20
)
2
=
2.5
×
1
0
−
21
M
.
Practice Ionic Equilibrium II
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