JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ia201
A diprotic acid HX2A has pKa1=3.0 and pKa2=7.0. Select the correct statement(s).
AA solution of the pure salt NaHA has pH≈5.0
BAt pH=5.0 the average charge per acid molecule is −1.5
CAt pH=5.0, [HX2A]=[AX2−]
DAt pH=7.0, less than 0.01% of the total acid is HX2A
Answer: A, C, D
pH(NaHA)=(3.0+7.0)/2=5.0. At pH=5, [HX2A]/[HAX−]=10−2=[AX2−]/[HAX−], so [HX2A]=[AX2−]. At pH=7.0 the fraction of HX2A is 5.0×10−5, below 10−4. At pH=5 almost all is HAX−, so the average charge is close to −1, not −1.5.