JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ia127
A 0.20M solution of NaA (HA: Ka=2.0×10−5) is diluted to 0.0020M at 298 K. Use h=Kh/C and [OHX−]=KhC. Which statements are correct?
AThe degree of hydrolysis increases from 5.0×10−5 to 5.0×10−4, i.e. it becomes 10 times larger.
BThe pH decreases from 9.00 to 8.00.
CKh decreases 100-fold on dilution.
D[OHX−] after dilution is 1.0×10−5M (unchanged).
Answer: A, B
Kh=Kw/Ka=5.0×10−10 is constant. h rises from 5.00e−05 to 5.00e−04 (factor 10). [OHX−] falls from 1.0e−05 to 1.0e−06M and the pH from 9.00 to 8.00. Kh depends only on temperature.