JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ia126
Three sodium salts NaA, NaB and NaC are made up as 0.10M solutions. The conjugate acids have Ka values 1.0×10−4 (HA), 1.0×10−6 (HB) and 1.0×10−8 (HC). Use pH=7+21(pKa+logC) and h=Kw/(KaC). Which statements are correct?
AThe pH of NaC exceeds that of NaA by 2.0 units.
BThe degree of hydrolysis of NaC is 10 times that of NaA.
CThe pH of NaB is 9.5.
DAX− is the strongest conjugate base of the three.
Answer: A, C
pH values: NaA 8.5, NaB 9.5, NaC 10.5, so the first and third statements hold. h=Kw/(KaC) gives 3.16e−05, 3.16e−04, 3.16e−03, so h(NaC)/h(NaA)=100, not 10. The weakest acid HC has the strongest conjugate base CX−.