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Ionic Equilibrium II
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Salt hydrolysis: pH of salts of weak acid or weak base
JEE Main level
Numerical answer
Difficulty 2 of 3
ia119
Find the pH of
0.10
M
NaF
at 298 K. (
K
a
of HF
=
6.8
×
1
0
−
4
; use
pH
=
7
+
2
1
(
p
K
a
+
lo
g
C
)
.) Give the answer to two decimals.
Numerical answer type, tolerance 0.01.
Answer: 8.083746
p
K
a
=
−
lo
g
(
6.8
×
1
0
−
4
)
=
3.167
.
pH
=
7
+
2
1
(
3.167
−
1.000
)
=
8.08
.
Practice Ionic Equilibrium II
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