JEE Main levelSingle correct optionDifficulty 2 of 3ia117
The pH of 0.10MCHX3COONa (Ka=1.8×10−5) is calculated by the usual hydrolysis formula. The solution is now diluted to 100 times its volume with water. Assuming the same formula holds, the new pH is
A8.87
B9.87
C8.37
D7.87
Answer: D
pH=7+21(pKa+logC). Initially pH=8.87. A 100-fold dilution lowers logC by 2, so pH falls by 1: pH=7.87.