A mixture is prepared from 50 mL of 0.10 M HCl and 50 mL of 0.10 M CH3COOH (pK_a = 4.74). It is then treated with 70 mL of 0.10 M NaOH. With log 2 = 0.301 and log 3 = 0.477, the pH is

JEE Advanced levelSingle correct optionDifficulty 3 of 3ia103

A mixture is prepared from $50 mL$ of $0.10 M$ $HCl$ and $50 mL$ of $0.10 M$ $CH X_{3} COOH$ ( $p K_{a} = 4.74$ ). It is then treated with $70 mL$ of $0.10 M$ $NaOH$ . With $lo g 2 = 0.301$ and $lo g 3 = 0.477$ , the pH is

The strong acid is neutralised first:

5 mmol

HCl

uses

5

of the

7 mmol

NaOH

. The remaining

2 mmol

converts

2

5 mmol

acetic acid to acetate, leaving

HA = 3

and

A X^{-} = 2

pH = 4.74 + lo g (2/3) = 4.74 + 0.301 - 0.477 = 4.56

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