Answer: A, B
pH=pKa+log(0.10/0.10)=4.74. Adding 0.010 mol NaOH: acid 0.09, salt 0.11, so pH =4.74+log(0.11/0.09)=4.83. A buffer's pH depends on the ratio, so tenfold dilution leaves it near 4.74 (the 5.74 claim is false). Adding 0.10 mol HCl converts all acetate to acetic acid (about 0.20 M CHX3COOH), giving pH near 2.72, not 4.74.