JEE Advanced levelNumerical answerDifficulty 3 of 3ia016
A 0.050 M solution of the chloride BCl of a weak base BOH has pH 5.45 at 298 K. Using Kh=[HX+]2/c (valid for small hydrolysis), find Kb of BOH and report it in units of 10−5, to two decimal places. Take Kw=1.0×10−14.
Numerical answer type, answer in x 10^-5, tolerance 0.03.
Answer: 3.97 x 10^-5
[HX+]=10−5.45=3.548e−06 M. Kh=[HX+]2/c=2.518e−10. Kb=Kw/Kh=3.972e−05=3.97×10−5.