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JEE Advanced levelNumerical answerDifficulty 3 of 3ig156

$PCl X_{5}$ (molar mass $208.5$ ) dissociates as $PCl X_{5} PCl X_{3} + Cl X_{2}$ . The observed vapour density of the equilibrium mixture at a certain temperature is $80$ . The degree of dissociation (two decimals) is

Numerical answer type, tolerance 0.01.

Answer: 0.3

Theoretical vapour density

D = 208.5/2 = 104.25

. For

1 mol

becoming

1 + α

:

α = \frac{D - d}{d} = \frac{104.25 - 80}{80} = 0.3031 \approx 0.30

.

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