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JEE Advanced levelNumerical answerDifficulty 3 of 3ig101

The ratio of the rms speed of $He$ (molar mass 4) at $400 K$ to the rms speed of $CH X_{4}$ (molar mass 16) at $100 K$ , to two decimals, is

Numerical answer type, tolerance 0.02.

Answer: 4

u_{rms} = 3 RT / M

. Ratio

= \frac{T _{He} / M _{He}}{T _{CH X_{4}} / M _{CH X_{4}}} = \frac{400/4}{100/16} = \frac{100}{6.25} = 16 = 4.00

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