The average translational kinetic energy of a single molecule of an ideal gas at 400 K, taking k_B = 1.38 x 10^-23 J K^-1, expressed in units of 10^-21 J (two decimals), is

JEE Advanced levelNumerical answerDifficulty 3 of 3ig100

The average translational kinetic energy of a single molecule of an ideal gas at $400 K$ , taking $k_{B} = 1.38 \times 1 0^{- 23} J K^{- 1}$ , expressed in units of $1 0^{- 21} J$ (two decimals), is

Numerical answer type, answer in x10^-21 J, tolerance 0.02.

\overline{K E} = \frac{3}{2} k_{B} T = 1.5 \times 1.38 \times 1 0^{- 23} \times 400 = 8.28 \times 1 0^{- 21} J

. This is independent of the gas.