An ideal gas is kept in a $4.0 L$ container at $300 K$ and $3.0 atm$ . The container has a relief valve that opens whenever the pressure exceeds $3.0 atm$ . The gas is slowly heated to $400 K$ . The percentage of the original gas that escapes (nearest integer) is

Numerical answer type, answer in %, tolerance 0.5.

Answer: 25 %

400 K

the pressure is held at

3.0 atm

in the same volume, so

n_{2} / n_{1} = T_{1} / T_{2} = 300/400 = 0.75

. Fraction escaped

= 1 - 0.75 = 0.25

, i.e.

25%