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JEE Main levelSingle correct optionDifficulty 2 of 3ig075

At a given temperature the rms speed of $SO X_{2}$ (molar mass 64) molecules is $u$ . At the same temperature the rms speed of $CH X_{4}$ (molar mass 16) molecules is

A $2 u$
B $4 u$
C $u /2$
D $u /4$

Answer: A

u_{rms} \propto 1/ M

at constant

T

.

\frac{u _{CH X_{4}}}{u _{SO X_{2}}} = \frac{64}{16} = 2

, so

2 u

.

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